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История изменений

Исправление frozenix, (текущая версия) :

хотя не в этом проблема

#include <stdio.h>
#include <stdlib.h>

long pow(double a, double b)
{
  printf("DEBUG: a = %f, b = %f\n", a, b);
  if(b <= 0) return 1;
  if(b == 1) return a;
  return a * pow(a, b - 1);
}

int main(int argc, char *argv[])
{
  printf("%ld", pow(3, 2));
}

andrew@andrew-desktop ~ $ gcc test.c -o test
test.c:5:6: warning: conflicting types for built-in function ‘pow’ [enabled by default]
andrew@andrew-desktop ~ $ ./test
DEBUG: a = 3.000000, b = 2.000000
DEBUG: a = 3.000000, b = 1.000000
9

#include <stdio.h>
#include <stdlib.h>

double pow(double a, double b)
{
  printf("DEBUG: a = %f, b = %f\n", a, b);
  if(b < 0) return 1;
  return a * pow(a, b - 1);
}

int main(int argc, char *argv[])
{
  printf("%f", pow(3, 2));
}

andrew@andrew-desktop ~ $ gcc test.c -o test
andrew@andrew-desktop ~ $ ./test 
9.000000

Исходная версия frozenix, :

хотя не в этом проблема

#include <stdio.h>
#include <stdlib.h>

long pow(double a, double b)
{
  printf("DEBUG: a = %f, b = %f\n", a, b);
  if(b < 0) return 1;
  return a * pow(a, b - 1);
}

int main(int argc, char *argv[])
{
  printf("%ld", pow(3, 2));
}

andrew@andrew-desktop ~ $ gcc test.c -o test
test.c:5:6: warning: conflicting types for built-in function ‘pow’ [enabled by default]
andrew@andrew-desktop ~ $ ./test 
DEBUG: a = 3.000000, b = 2.000000
DEBUG: a = 3.000000, b = 1.000000
DEBUG: a = 3.000000, b = 0.000000
DEBUG: a = 3.000000, b = -1.000000
27

#include <stdio.h>
#include <stdlib.h>

double pow(double a, double b)
{
  printf("DEBUG: a = %f, b = %f\n", a, b);
  if(b < 0) return 1;
  return a * pow(a, b - 1);
}

int main(int argc, char *argv[])
{
  printf("%f", pow(3, 2));
}

andrew@andrew-desktop ~ $ gcc test.c -o test
andrew@andrew-desktop ~ $ ./test 
9.000000