возможно ли двойное раскрытие дефайнов в С

#include <stdlib.h>
#include <string.h>

#define par1 "10, 20"
#define sum(a, b) (a + b)
#define sum_str(str) sum(atoi(par1), atoi(strchr(par1, ',') + 1))

int main(void) {
   int c = sum_str(par1);
   printf("%d\n", c);
   return 0;
}

#define par1 10, 20

#define sum(a, b) (a + b)

#define CALL(fun, arg) fun ( arg )

void main(void) {
      printf("%d\n",CALL(sum, par1));
}

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define par1 "10, 20"
#define sum(a, b) (a + b)
//#define sum_str(str) sum(atoi(par1), atoi(strchr(par1, ',') + 1))
#define sum_str(str) sum(atoi(str), atoi(strchr(str, ',') + 1))

int main(void) {
   int c = sum_str(par1);
   printf("%d\n", c);
   return 0;
}

#include <stdio.h>
#include <string.h>
#include <stdarg.h>

#define NUMARGS(...)  (sizeof((int[]){__VA_ARGS__})/sizeof(int))
#define SUM(...)  (sum(NUMARGS(__VA_ARGS__), __VA_ARGS__))

void sum(int numargs, ...);

int main(int argc, char *argv[]) {

    SUM(1);
    SUM(1, 2);
    SUM(1, 2, 3);
    SUM(1, 2, 3, 4);

    return 1;
}

void sum(int numargs, ...) {
    int     total = 0;
    va_list ap;

    printf("sum() called with %d params:", numargs);
    va_start(ap, numargs);
    while (numargs--)
        total += va_arg(ap, int);
    va_end(ap);

    printf(" %d\n", total);

    return;
}

#define par1 10, 20

#define sum_(a, b) (a + b)
#define sum(...) sum_(__VA_ARGS__)

void main(void) {
    int c = sum(par1);
    int d = sum(10, 20);
}