Добрый день.
Есть следующий текст:
#!/bin/bash
#
NAME="my_server" # Name of the application
DJANGODIR=$MY_HOME # Django project directory
SOCKFILE=$FOR_SOME/run/gunicorn.sock # we will communicte using this unix socket
USER=ubuntu # the user to run as
GROUP=webapps # the group to run as
NUM_WORKERS=3 # how many worker processes should Gunicorn spawn
DJANGO_SETTINGS_MODULE=my_server.settings # which settings file should Django use
DJANGO_WSGI_MODULE=my_server.wsgi # WSGI module name
#
echo "Starting $NAME as `whoami`"
#
# Activate the virtual environment
cd $DJANGODIR
source ../bin/activate
export DJANGO_SETTINGS_MODULE=$DJANGO_SETTINGS_MODULE
export PYTHONPATH=$DJANGODIR:$PYTHONPATH
#
# Create the run directory if it doesn't exist
RUNDIR=$(dirname $SOCKFILE)
test -d $RUNDIR || mkdir -p $RUNDIR
#
# Start your Django Unicorn
# Programs meant to be run under supervisor should not daemonize themselves (do not use --daemon)
exec ../bin/gunicorn ${DJANGO_WSGI_MODULE}:application \
--name $NAME \
--workers $NUM_WORKERS \
--user=$USER --group=$GROUP \
--bind=unix:$SOCKFILE \
--log-level=debug \
--log-file=$FOR_SOME/logs/gunicorn_my_server.log
Как этот текст записать в файл в bash скрипте? Через echo " не получается.