fdisk -lu /dev/sda | grep '^\/' | while read disk start other; do
    if [ ! "$((  $start % 2048 ))" -eq "0" ]; then
        echo "$disk not aligned";
    fi;
done

Total free space is 12 sectors (6.0 KiB)

Number  Start (sector)    End (sector)  Size       Code  Name
   1              40            2087   1024.0 KiB  EF02  BIOS boot partition
   2            2088      1953525128   931.5 GiB   FD00  Linux RAID

Command (? for help): p
Disk /dev/sda: 1953525168 sectors, 931.5 GiB
Logical sector size: 512 bytes
Disk identifier (GUID): 2710D8EF-4BA5-417E-9A71-F29508281DE6
Partition table holds up to 128 entries
First usable sector is 34, last usable sector is 1953525134
Partitions will be aligned on 8-sector boundaries
Total free space is 6 sectors (3.0 KiB)

Number  Start (sector)    End (sector)  Size       Code  Name
   1              40            2087   1024.0 KiB  EF02  BIOS boot partition
   2            2088      1953525134   931.5 GiB   FD00  Linux RAID

Command (? for help): p
Disk /dev/sdb: 1953525168 sectors, 931.5 GiB
Logical sector size: 512 bytes
Disk identifier (GUID): F396F739-049C-4EFE-AFD3-B11E062988F6
Partition table holds up to 128 entries
First usable sector is 34, last usable sector is 1953525134
Partitions will be aligned on 2048-sector boundaries
Total free space is 4067 sectors (2.0 MiB)

Number  Start (sector)    End (sector)  Size       Code  Name
   1            2048            4096   1.0 MiB     EF02  BIOS boot partition
   2            6144      1953525128   931.5 GiB   FD00  Linux RAID

// Compute sector alignment based on the current partitions (if any). Each
// partition's starting LBA is examined, and if it's divisible by a power-of-2
// value less than or equal to the DEFAULT_ALIGNMENT value (adjusted for the
// sector size), but not by the previously-located alignment value, then the
// alignment value is adjusted down. If the computed alignment is less than 8
// and the disk is bigger than SMALLEST_ADVANCED_FORMAT, resets it to 8. This
// is a safety measure for WD Advanced Format and similar drives. If no partitions
// are defined, the alignment value is set to DEFAULT_ALIGNMENT (2048) (or an
// adjustment of that based on the current sector size). The result is that new
// drives are aligned to 2048-sector multiples but the program won't complain
// about other alignments on existing disks unless a smaller-than-8 alignment
// is used on big disks (as safety for WD Advanced Format drives).
// Returns the computed alignment value.
uint32_t GPTData::ComputeAlignment(void) {
   uint32_t i = 0, found, exponent = 31;
   uint32_t align = DEFAULT_ALIGNMENT;

   if (blockSize > 0)
      align = DEFAULT_ALIGNMENT * SECTOR_SIZE / blockSize;
   exponent = (uint32_t) log2(align);
   for (i = 0; i < numParts; i++) {
      if (partitions[i].IsUsed()) {
         found = 0;
         while (!found) {
            align = UINT64_C(1) << exponent;
            if ((partitions[i].GetFirstLBA() % align) == 0) {
               found = 1;
            } else {
               exponent--;
            } // if/else
         } // while
      } // if
   } // for
   if ((align < MIN_AF_ALIGNMENT) && (diskSize >= SMALLEST_ADVANCED_FORMAT))
      align = MIN_AF_ALIGNMENT;
   sectorAlignment = align;
   return align;
} // GPTData::ComputeAlignment()